Mass to Mass Conversions

mass to mass problems are additional conversions.

Grams of A                                                                      Grams of B
            |                                                                                     |
Moles of A -  >>Multiplied boy the stoichiometric ratio >>> Moles of B

ex: lead (IV) nitrate reacts with 5.0 g of Pottasium iodide. How many grams of lead (IV) nitrate are required for a complete reaction?

Pb (NO3)4  + 4KI   > 4KNO3  = PbI4
5.0g x (1 mole over 166 g/mol) x 1/4  x (455 over 1 mole) = 3.4 g

ex2: how many grams of O2  are produced ffrom the decomposition of 3.og of Pottasium chlorate?


2KClO3 >> @K + Cl2 + 3O2


3.0 g x (1 mole over 122.6 g  x 3/2 x (32 over 1 mol) = 1.2 g


-Paul Dinh